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60=2x^2-7x
We move all terms to the left:
60-(2x^2-7x)=0
We get rid of parentheses
-2x^2+7x+60=0
a = -2; b = 7; c = +60;
Δ = b2-4ac
Δ = 72-4·(-2)·60
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*-2}=\frac{-30}{-4} =7+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*-2}=\frac{16}{-4} =-4 $
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